X^2+24x-328=0

Solution for X^2+24x-328=0 equation:

X^2+24X-328=0

a = 1; b = 24; c = -328;
Δ = b2-4ac
Δ = 242-4·1·(-328)
Δ = 1888
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1888}=\sqrt{16*118}=\sqrt{16}*\sqrt{118}=4\sqrt{118}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{118}}{2*1}=\frac{-24-4\sqrt{118}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{118}}{2*1}=\frac{-24+4\sqrt{118}}{2}
$